You're viewing a single thread.
-3 = 3
Absolutely.
Adding 3 on both sides
3-3=3+3
0 = 6
1•0 = 6
1 = 6/0
1 = inf
Multiplying e^(iπ) on both sides,
e^(iπ) = - inf
iπ = ln|-inf|
π = ln|-inf| ÷ i
1/0 isn't infinity though.
Like if everything else is true.
1/0 can be infinity as a limiting case but not always. So imma use what i like since i also took ln|x| (took mod out of nowhere just to make it positive)
Division is repeated subtraction. How many times can you subtract 0 from 1?
I gotta say second half of that goes over my head, but I raise my hat to you
I remember you. You saved me from rickroll on xkcd
Damn me
it starts out okay but 6/0 is not inf.
Its just the joke i take watever i want. There is | | inside log which is just made up. 6/x as x->0 is infinity though so i'mma use that